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Automatic Control Systems(자동제어시스템) 9판 다운로드


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Automatic Control Systems(자동제어시스템) 9판 솔루션 Golnaraghi, Farid / Benjamin C.Kuo 저 챕터2~10까지

Ninth Edition

Farid Golnaraghi ? Benjamin C. Kuo

So lu tio ns

M an ua l

Automatic?Control?Systems,?9th?Edition? A ? ?

?Chapter?2?Solutions n

?Golnaraghi,?Kuo? r

Chapter 2 C 2?1??(a)??Poles 2 s:??s?=?0,?0,??1,?? ?10;? ?
? ? ? ??Zeros s:??s?=??2,?∞,?∞,?∞.? ? ? ? ? ? ? ? ?

(b) ?Poles:??s?=??2, ,??2;?
???????Zeros:??s?=?0. ???????The?pole?and?zero?at?s?=??1?c cancel?each?other.? t

????

(c)?? ( Poles:??s?=?0,??1?+?j,??1???j;?
? ??Zeros s:??s?=??2.?

?

(d)??Poles:??s =?0,??1,??2,?∞.?

?? 2-2) 2 a) b) c)

?

2-3) 2
MATLAB?code M e:?

2?1? ?

Automatic?Control?Systems,?9th?Edition? ? ?
clear all; s = tf(`s`)

?Chapter?2?Solutions?

?Golnaraghi,?Kuo?

`Generated transfer function:` Ga=10*(s+2)/(s^2*(s+1)*(s+10)) `Poles:` pole(Ga) `Zeros:` zero(Ga)

`Generated transfer function:` Gb=10*s*(s+1)/((s+2)*(s^2+3*s+2)) `Poles:`; pole(Gb) `Zeros:` zero(Gb)

`Generated transfer function:` Gc=10*(s+2)/(s*(s^2+2*s+2)) `Poles:`; pole(Gc) `Zeros:` zero(Gc)

`Generated transfer function:` Gd=pade(exp(-2*s),1)/(10*s*(s+1)*(s+2)) `Poles:`; pole(Gd) `Zeros:` zero(Gd)

2?2? ?

Automatic?Control?Systems,?9th?Edition? ? ? ? Poles?and?zeros?of?the?above?functions:?? (a)?? Poles:?????0?????0????10?????1? Zeros:?????2? (b)???? Poles:??????2.0000????2.0000????1.0000? Zeros:?????0?????1? (c)? Poles:? ?????0??????????? ???1.0000?+?1.0000i? ???1.0000???1.0000i? Zeros:?????2? Generated?transfer?function:?

?Chapter?2?Solutions?

?Golnaraghi,?Kuo?

(d)?using?first?order?Pade?approximation?for?exponential?term? Poles:? ????????0??????????? ???2.0000??????????? ???1.0000?+?0.0000i? ???1.0000???0.0000i? ? Zeros:? ?????1? ?

2?3? ?

Automatic?Control?Systems,?9th?Edition? ? ?

?Chapter?2?Solutions?

?Golnaraghi,?Kuo?

2-4) Mathematical representation: In all cases substitute and simplify. The use MATLAB to verify.
R= 10 22 + ω 2 1 + ω 2 102 + ω 2 ; ?ω 2 (ω 2 + 1)(ω 2 + 100)

10( jω + 2) 2 2 2 φ1 = tan ?1 2 + ω ?ω ( jω + 1)( jω + 10) 2 10( jω + 2) ( ? jω + 1)(? jω + 10) 22 + ω 2 = × 2 ?ω ( jω + 1)( jω + 10) (? jω + 1)(? jω + 10) ?ω 2 10( jω + 2)( ? jω + 1)(? jω + 10) a) ? = φ2 = tan ?1 1 + ω 2 2 2 1 ?ω (ω + 1)(ω + 100) 1+ ω2 jω + 2 ? jω + 1 ? jω + 10 =R ?ω 22 + ω 2 1 + ω 2 102 + ω 2 2 2 = R(e jφ1 e jφ2 e jφ3 ) φ3 = tan ?1 10 + ω 10
102 + ω 2

ω

?

φ = φ1 + φ2 + φ3
?

R=

10 2 2 φ1 = tan ?1 1 + ω ( jω + 1) ( jω + 3) 1 10 (? jω + 1)(? jω + 1)(? jω + 3) 1+ ω2 = × ( jω + 1)( jω + 1)( jω + 3) ( ? jω + 1)(? jω + 1)(? jω + 3) ?ω 2 10(? jω + 1)(? jω + 1)(? jω + 3) ? b) = φ2 = tan ?1 1 + ω 1 (ω 2 + 1) 2 (ω 2 + 9) 1+ ω2 ? jω + 1 ? jω + 1 ? jω + 3 R = ?ω 1+ ω2 1+ ω2 9 + ω2 2 = R (e jφ1 e jφ2 e jφ3 ) φ3 = tan ?1 9 + ω 3
9 + ω2

10 1 + ω 2 9 + ω 2 ; (ω 2 + 1) 2 (ω 2 + 9) ?ω

φ = φ1 + φ2 + φ3

2?4? ?

Automatic?Control?Systems,?9th?Edition? ? ?

?Chapter?2?Solutions?

?Golnaraghi,?Kuo?

10 jω ( j 2ω + 2 ? ω 2 ) ?10 j (2 ? ω 2 ? j 2ω ) = × ω ( j 2ω + 2 ? ω 2 ) (2 ? ω 2 ? j 2ω ) 10(?2ω ? (2 ?


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[문서정보]

문서분량 : 947 Page
파일종류 : PDF 파일
자료제목 :
파일이름 : 솔루션 전기전자 Automatic Control Systems_Kuo_9th Edition - Solutions Manual.pdf
키워드 : Golnaraghi,Farid,Benjamin,C,Kuo,Automatic,Control,Systems,자동제어시스템,자동제어



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