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대학물리학 12판 physics 12ed - 영문 Physics 12ed - Young and Freedman

대학물리학 12판 physics 12ed - 영문 Physics 12ed - Young and Freedman - 미리보기를 참고 바랍니다.

UNITS, PHYSICAL QUANTITIES AND VECTORS

1

1.1.

IDENTIFY: Convert units from mi to km and from km to ft. SET UP: 1 in. = 2.54 cm , 1 km = 1000 m , 12 in. = 1 ft , 1 mi = 5280 ft . ? 5280 ft ?? 12 in. ?? 2.54 cm ?? 1 m ?? 1 km ? EXECUTE: (a) 1.00 mi = (1.00 mi) ? ?? ?? ?? 2 ?? 3 ? = 1.61 km ? 1 mi ?? 1 ft ?? 1 in. ?? 10 cm ?? 10 m ?

1.2.

? 103 m ?? 102 cm ? ? 1 in. ?? 1 ft ? 3 (b) 1.00 km = (1.00 km) ? ?? ?? ?? ? = 3.28 × 10 ft 1 km ?? 1 m ? ? 2.54 cm ?? 12 in. ? ? EVALUATE: A mile is a greater distance than a kilometer. There are 5280 ft in a mile but only 3280 ft in a km. IDENTIFY: Convert volume units from L to in.3 . SET UP: 1 L = 1000 cm3 . 1 in. = 2.54 cm
? 1000 cm3 ? ? 1 in. ? 3 0.473 L × ? ?×? ? = 28.9 in. . ? 1 L ? ? 2.54 cm ? EVALUATE: 1 in.3 is greater than 1 cm3 , so the volume in in.3 is a smaller number than the volume in cm3 , which is 473 cm3 . IDENTIFY: We know the speed of light in m/s. t = d / v . Convert 1.00 ft to m and t from s to ns. SET UP: The speed of light is v = 3.00 × 108 m/s . 1 ft = 0.3048 m . 1 s = 109 ns . 0.3048 m EXECUTE: t = = 1.02 × 10?9 s = 1.02 ns 3.00 × 108 m/s EVALUATE: In 1.00 s light travels 3.00 × 108 m = 3.00 × 105 km = 1.86 × 105 mi . IDENTIFY: Convert the units from g to kg and from cm3 to m3 . SET UP: 1 kg = 1000 g . 1 m = 1000 cm .
EXECUTE: EXECUTE:
3

1.3.

1.4.

g ? 1 kg ? ? 100 cm ? 4 kg × 11.3 ?×? ? = 1.13 × 10 3 ? cm ? 1000 g ? ? 1 m ? m3

3

1.5.

EVALUATE: The ratio that converts cm to m is cubed, because we need to convert cm3 to m3 . IDENTIFY: Convert volume units from in.3 to L. SET UP: 1 L = 1000 cm3 . 1 in. = 2.54 cm . EXECUTE:

( 327 in. ) × ( 2.54 cm in.) × (1 L 1000 cm ) = 5.36 L
3 3 3

1.6.

EVALUATE: The volume is 5360 cm3 . 1 cm3 is less than 1 in.3 , so the volume in cm3 is a larger number than the volume in in.3 . IDENTIFY: Convert ft 2 to m 2 and then to hectares. SET UP: 1.00 hectare = 1.00 × 104 m 2 . 1 ft = 0.3048 m . EXECUTE:

? 43,600 ft 2 ? ? 0.3048 m ? The area is (12.0 acres) ? ?? ? ? 1 acre ? ? 1.00 ft ?

2

? 1.00 hectare ? = 4.86 hectares . ? 4 2 ? ? 1.00 × 10 m ?

1.7.

EVALUATE: Since 1 ft = 0.3048 m , 1 ft 2 = (0.3048) 2 m 2 . IDENTIFY: Convert seconds to years. SET UP: 1 billion seconds = 1 × 109 s . 1 day = 24 h . 1 h = 3600 s . EXECUTE:

? 1 h ?? 1 day ? ? 1 y ? 1.00 billion seconds = (1.00 × 109 s ) ? ? = 31.7 y . ?? ?? ? 3600 s ?? 24 h ? ? 365 days ?
1-1

1-2

Chapter 1

1.8.

EVALUATE: The conversion 1 y = 3.156 × 107 s assumes 1 y = 365.24 d , which is the average for one extra day every four years, in leap years. The problem says instead to assume a 365-day year. IDENTIFY: Apply the given conversion factors. SET UP: 1 furlong = 0.1250 mi and 1 fortnight = 14 days. 1 day = 24 h.

1.9.

? 0.125 mi ?? 1 fortnight ?? 1 day ? furlongs fortnight ) ? ? = 67 mi/h ?? ?? ? 1 furlong ?? 14 days ? ? 24 h ? EVALUATE: A furlong is less than a mile and a fortnight is many hours, so the speed limit in mph is a muc


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